Consider the circuit shown in the figure below. (λ=0) Values of V1=6V and V2=2V. Value of IDThe two transistors Q1 and Q2 are exactly matched with each other.μnCoxWL=10 mA/V2,Vt=0.5V(λ=0) Values of V1=6V and V2=2V. Value of ID in mA is 11.25

Consider the circuit shown in the figure below. (λ=0) Values of V1=6

1.	Consider the circuit shown in the figure below. (λ=0) Values of V1=6V and V2=2V. Value of IDThe two transistors Q1 and Q2 are exactly matched with each other.μnCoxWL=10 mA/V2,Vt=0.5V(λ=0) Values of V1=6V and V2=2V. Value of ID in mA is 11.25
Answer» $C o n s i d e r t h e c i r c u i t s h o w n i n t h e f i g u r e b e l o w .$ $(λ = 0) V a l u e s o f V_{1} = 6 V a n d V_{2} = 2 V . V a l u e o f I_{D}$ $The two transistors Q_{1} and Q_{2} are exactly matched with each other. \frac{μ_{n} C_{o x} W}{L} = 10 {mA/V}^{2}, V_{t} = 0.5 V$ ( $λ = 0) V a l u e s o f V_{1} = 6 V a n d V_{2} = 2 V . V a l u e o f I_{D} i n m A i s$ 11.25

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Consider the circuit shown in the figure below. (λ=0) Values of V1=6V and V2=2V. Value of IDThe two transistors Q1 and Q2 are exactly matched with each other.μnCoxWL=10 mA/V2,Vt=0.5V(λ=0) Values of V1=6V and V2=2V. Value of ID in mA is 11.25

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