Consider the compounds, BCl_(3)" and "C"C"l_(4). How will they behave with water ? Justify.

Consider the compounds, BCl_(3)" and "C"C"l_(4). How will they behave

1.	Consider the compounds, BCl_(3)" and "C"C"l_(4). How will they behave with water ? Justify.
Answer» Solution :B ATOM in `BCl_3` has only six electrons. Thus, `BCl_3` is an electron-deficient MOLECULE and ACCEPTS a pair of electrons DONATED by water. Therefore, when treated with water, `BCl_3` undergoes hydrolysis to form boric acid and HCI. `BCl_3 + 3H_2 O to H_3 BO_3 + 3HCL` On the other hand, C atom in `C Cl_4` possesses an octet and has no tendency to accept or donate a pair of electrons. Hence, it does not react with water.