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Consider the compounds, BCl_3 and C Cl_4. How will they behave with water ? Justify. |
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Answer» Solution :Being a Lewis ACID, `BCl_3` readily UNDERGOES hydrolysis. Boric acid is FORMED as a result. `BCl_3 + 2H_2O to 3HCl + B(OH)_3` `C Cl_4` completely resists hydrolysis. Carbon does not have any vacant orbital. Hence, it can not accept electrons from water to form an intermediate. When `C Cl_4` and water are MIXED, they form separate layers. `C Cl_4 + H_2O to` No Reaction |
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