1.

Consider the compounds, `BCl_(3)` and `C Cl_(4)`.How will they behave with water? Justify.

Answer» Being a Lewis acid, `BCl_(3)` readily undergoes hydrolysis. Boric acid is formed as a result.
`BCl_(3)+3H_(2)Orarr3HCl+B(OH)_(3)`
`C"C"l_(4)` completely resists hydrolysis. Carbon does not have any vacant orbital. Hence, it cannot accept electrons from water to form an intermediate. When `C"C"l_(4)` and water are mixed, they form separate layers.
`C"C"l_(4)+H_(2)Orarr`No reaction


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