Consider the compounds, BCl3 and CCl4 . How will they behave with wate

1.	Consider the compounds, BCl3 and CCl4 . How will they behave with water?
Answer» The B atom in BCl₃ has only six electrons in the valence shell and hence is an electrondecient molecule. It easily accepts a pair of electrons donated by water and hence BCl₃ undergoes hydrolysis to form boric acid (H₃BO₃) and HCl. BCl₃ + 3H₂O → H₃BO₃ + 3HCl In contrast, C atom in CCl₄ has 8 electrons in the valence shell. Therefore, it is an electron-precise molecule. As a result, it neither accepts nor donates a pair of electrons. In simple words, it does not accept a pair of electrons from H₂O molecule and hence CCl₄ does not undergo hydrolysis in water.

Consider the compounds, BCl3 and CCl4 . How will they behave with water?

Answer»

The B atom in BCl₃ has only six electrons in the valence shell and hence is an electrondecient molecule. It easily accepts a pair of electrons donated by water and hence BCl₃ undergoes hydrolysis to form boric acid (H₃BO₃) and HCl.

BCl₃ + 3H₂O → H₃BO₃ + 3HCl

In contrast, C atom in CCl₄ has 8 electrons in the valence shell. Therefore, it is an electron-precise molecule. As a result, it neither accepts nor donates a pair of electrons. In simple words, it does not accept a pair of electrons from H₂O molecule and hence CCl₄ does not undergo hydrolysis in water.

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