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Consider the cube in the first octant with sides OP,OQ and OR of length 1, along the x-axis, y-axis and z-axis, respectively, where O(0,0,0) is the origin. Let S(12,12,12) be the centre of the cube and T be the vertex of the cube opposite to the origin O such that S lies on the diagonal OT.If →p=−→SP,→q=−−→SQ,→r=−−→SR and →t=−→ST, then the value of |(→p×→q)×(→r×→t)| is

Answer» Consider the cube in the first octant with sides OP,OQ and OR of length 1, along the x-axis, y-axis and z-axis, respectively, where O(0,0,0) is the origin. Let S(12,12,12) be the centre of the cube and T be the vertex of the cube opposite to the origin O such that S lies on the diagonal OT.If p=SP,q=SQ,r=SR and t=ST, then the value of |(p×q)×(r×t)| is


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