Consider the curve sinx+siny=1, lying in the first quadrant , thenList- IList-II(I)limx→π/2d2ydx2=(P) 0(II)limx→0+x3/2d2ydx2=(Q) 1(III) limx→0+x2d2ydx2=(R) 1√2(IV)limx→π/2dydx=(S) 12√2(T) √2(U) 3 Which of the following is the only INCORRECT combination?

Consider the curve sinx+siny=1, lying in the first quadrant , thenList

1.	Consider the curve sinx+siny=1, lying in the first quadrant , thenList- IList-II(I)limx→π/2d2ydx2=(P) 0(II)limx→0+x3/2d2ydx2=(Q) 1(III) limx→0+x2d2ydx2=(R) 1√2(IV)limx→π/2dydx=(S) 12√2(T) √2(U) 3 Which of the following is the only INCORRECT combination?
Answer» Consider the curve $sin x + sin y = 1$ , lying in the first quadrant , then $\begin{matrix} List- I & List-II (I) & lim x \to π / 2 \frac{d^{2} y}{d x^{2}} = & (P) & 0 (II) & lim x \to 0^{+} x^{3 / 2} \frac{d^{2} y}{d x^{2}} = & (Q) & 1 (III) & lim x \to 0^{+} x^{2} \frac{d^{2} y}{d x^{2}} = & (R) & \frac{1}{\sqrt{2}} (IV) & lim x \to π / 2 \frac{d y}{d x} = & (S) & \frac{1}{2 \sqrt{2}} (T) & \sqrt{2} (U) & 3 \end{matrix}$ Which of the following is the only INCORRECT combination?