1.

Consider the decomposition of solid NH_(4)HS in a flask containing NH_(3)(g) at a pressure of 2 atm. What will be the partial pressure of NH_(3)(g) "and" H_(2)S(g) after the equilibrium has been attained? K_(p) for the reaction is 3.

Answer»

`P_(NH_(3))=4 "atm", P_(H_(2))s=2` atm
`P_(MH_(3))=1.732 "atm", P_(h_2)s=1.732` atm
`P_(NH_(3))=3 "atm", P_(H_(2))s=1` atm
`P_(NH_(3))=1 "atm", P_(H_(2))s=1` atm

Solution :N//A


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