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Consider the diffraction patern for a small pinhole. As the size of the hole is increasedA. the size decreases.B. the intensity increasesC. the size increasesD. the intensity decreases. |
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Answer» Correct Answer - A::B `beta = 2lambda (D)/(d)` is the width of primary maximum in difraction pattern. Intensity `I = I_(0) ((sin alpha)/(alpha))^(2)` where `alpha = (pi d)/(lambda) sin theta` |
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