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Consider the diffraction pattern for a small pinhole. As the size of the hole is increasedA. the size decreaseB. the intensity increaseC. the size increaseD. the intensity decrease |
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Answer» Correct Answer - A::B (a,b) (a) When a decrease w increases. So, size decreases. (b) Now, light energy is distributed over a small are and intensity `prop(1)/("area")` as area is decreasing so intensity increases. |
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