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Consider the equation `(1+a+b)^2=3(1+a^2+b^2)`. where a, b are real numbers.thenA. There is no solution pair (a,b)B. there are infinitely many solution pairs (a,b)C. there are exactly two solution pairs (a,b)D. there is exactly one solution pair (a,b) |
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Answer» Correct Answer - d `(1+a+b)^(2)=3 (1+a^(2)+b^(2))` `1.a.+a.b+1.b=1^(2)+a^(2)+b^(2)` 1=a=b exactly one pair. |
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