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In a Mathematics test, the average marks of boys is `x%` and the average marks of girls is `y%` with `xney.` If the average marks of all students is `z%` the ration of the number of girls to the total number of students isA. `(z-x)/(y-x)`B. `(z-y)/(y-x)`C. `(z+y)/(y-x)`D. `(z+x)/(y-x)` |
Answer» Correct Answer - A Given Let no. of Boys = B `&` no of girls = G `therefore` Sum of marks obtained by boys = b.x `therefore` Sum of marks obtained by girls = Gy Now, given `(Bx+Gy)/(B+G)=z` `B(x-z)=G(z-y)` `(B)/(G)=(z-y)/(x-z)` `"Add " 1` `(B)/(G)+1=(z-y)/(x-z)+1` `rArr(B+G)/(G)=(x-y)/(x-z)` `rArr(G)/(B+G)=(z-x)/(y-x)` |
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