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Consider the equation `d/(dt)(int vec(F). dvec(S))=A(vec(F).vec(p))` where `vec(F) equiv` force, `vec(s) equiv` displacement, t `equiv` time and `vec(p)`= momentum. The dimensional formula of A will beA. `M^(0)L^(0)T^(0)`B. `ML^(0)T^(0)`C. `M^(-1)L^(0)T^(0)`D. `M^(0)L^(0)T^(-1)` |
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Answer» `[(d)/(dt)(intvecF.dvecS)]=[A(vecF.vecp)]rArr[(Fs)/(t)]=[AFp]` `rArr[A]=[(s)/(pt)]=(L)/(MLT^(-1)xxT)=M^(-1)` |
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