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Consider the equation of a pair of straight lines as lambdax^(2)-10xy+12y^(2)+5x-16y-3=0.The point of intersection of lines is (alpha, beta). Then the value of alpha beta is |
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Answer» 35 Consider the HOMOGENEOUS PART `2x^(2)-10xy+12y^(2)=(x-2y)(2x-6)` `2x^(2)-10xy+12y^(2)+5x-16y-3` `-=(2x-6y+A)(x-2y+B)` Comparing coefficients , we get `A=-1,B=3` Hence , the lines are `2x-6y-1=0and x-2y+3=0`Solving , we get the intersection points as`(-10,-7//2)`. THEREFORE , Product `=35` |
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