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Consider the equilibrium `SO_(3) (g) hArr SO_(2) (g) + (1)/(2) O_(2) (g) " " K_(C ) = 1` What should be the initial concentration so that at equilibrium `[SO_(3)] = [O_(2)]`A. `(4)/(3) M`B. `(1)/(3)M`C. `(1)/(4)M`D. `(3)/(4)M` |
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Answer» Correct Answer - D `{:(,SO_(3) (g),hArr,SO_(2) (g),+,(1)/(2) O_(2) (g),K_(C) = 1,),(t = 0,C_(0),,0,,0,,),("conc.",,,,,,,),(t = t_("eqm"),C_(0) - x,,x,,(x)/(2),,),("conc.",,,,,,,):}` Given `[SO_(3)] = (O_(2)]` `C_(0) - x = (x)/(2)` `(3x)/(2) = C_(0) rArr x = (2C_(0))/(3)` at equilibrium `[O_(2)] = (x)/(2) = (C_(0))/(3), [SO_(2)] = x = (2C_(0))/(3), [SO_(3)] = C_(0) - x` `[SO_(3)] = C_(0) - (2C_(0))/(3)` `[SO_(3)] = (C_(0))/(3)` `K_(C) = 1 = ([SO_(2)] [O_(2)]^(1//2))/([SO_(3)]) = ((2C_(0))/(3) xx ((C_(0))/(3))^(1//2))/((C_(0))/(3))` `1 = 4 (C_(0))/(3)` `C_(0) = (3)/(4) M` |
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