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Consider the family of circles x^(2)+y^(2)-2x-2ay-8=0 passingthrough two fixed points A and B . Also, S=0 is a cricle of this family, the tangent to which at A and B intersect on the line x+2y+5=0. If the circle x^(2)+y^(2)-10x+2y=c=0 is orthogonal to S=0, then the value of c is |
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Answer» 8 So, by applying condition of orthogonal intersection, we get `2(-5)(-1)+2(1) (-3)= c-8` `:. C= 12` |
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