Consider the family of lines `(x-y-6) + lambda(2x + y + 3) = 0` and `(x + 2y-4) + mu(3x-2y-4)=0` . If the lines of these 2 families are at right angle to each other then the locus of their point of intersection, is

Consider the family of lines `(x-y-6) + lambda(2x + y + 3) = 0` and `(

1.	Consider the family of lines `(x-y-6) + lambda(2x + y + 3) = 0` and `(x + 2y-4) + mu(3x-2y-4)=0` . If the lines of these 2 families are at right angle to each other then the locus of their point of intersection, is
Answer» `l_1:(x-y-6)+lamda(2x+3+y)` , intersection point of these two lines is`(1,-5)`(found out by elimination) `l_2:(x+2y-4)+mu(3x-2y-4)`,intersection point of these two lines is`(2,1)`(found out by elimination) Let point of intersection be `(h,k)` given the two lines are perpendicular to each other `(k+5)/(h-1) xx (k-1)/(h-2)=-1` =>`h^2+k^2-3h+4k-3=0` .(locus of point of intersection)

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Consider the family of lines `(x-y-6) + lambda(2x + y + 3) = 0` and `(x + 2y-4) + mu(3x-2y-4)=0` . If the lines of these 2 families are at right angle to each other then the locus of their point of intersection, is

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