1.

Consider the Fig. 3.2 and answer the following questions.

Answer»

(i) Cell ‘B’ will act as electrolytic cell as it has lower emf

∴ The electrode reactions will be:

Zn2+ + 2e ⎯→ Zn at cathode

Cu → Cu2+ + 2eat anode

(ii) Now cell ‘B’ acts as galvanic cell as it has higher emf and will push electrons into cell ‘A’.

The electrode reaction will be:

At anode : Zn → Zn2+ + 2e

At cathode : Cu2+ + 2e– ⎯→ Cu



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