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Consider the Fig. 3.2 and answer the following questions. |
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Answer» (i) Cell ‘B’ will act as electrolytic cell as it has lower emf ∴ The electrode reactions will be: Zn2+ + 2e– ⎯→ Zn at cathode Cu → Cu2+ + 2e– at anode (ii) Now cell ‘B’ acts as galvanic cell as it has higher emf and will push electrons into cell ‘A’. The electrode reaction will be: At anode : Zn → Zn2+ + 2e– At cathode : Cu2+ + 2e– ⎯→ Cu |
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