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Consider the following arrangement : If `O_(2)` and `N_(2)` are assumed to behave ideally, then on removing partition `X` (smoothly), then select incorrect option(s) for this process :A. `DeltaS_(says) lt0, DeltaS_(surr) lt 0`B. `DeltaS_(univ) gt 0`C. `DeltaU gt 0, DeltaH gt 0`D. `DeltaG lt 0` |
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Answer» Correct Answer - A::C `DeltaS_(sys)` is `+ ve` `DeltaS_("surr") = 0, DeltaH = 0, DeltaU = 0` `Delta G = DeltaH - Delta(TS)` `= 0 - TDeltaS` `= - TDeltaS` |
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