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Consider the following balanced chemical equation: `2A+4B_(2)+6C_(3)rarrP+2Q` If initially 6.023xx `10^(24)` atoms orf A, 448L of `B_(2)` gas at NTP and 960 gm of `C_(3)` gas are taken, which of the following is incorrect? [Given : Atomic mass of C=8]A. total number of species in final mixture is 4B. total number of species in final mixture is 3C. A and `B_(2)` both are present in limited amount amount.D. `C_(3)` is in excess. |
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Answer» `n_(A)=10` `n_(B)=20` `n_(C)=(960)/(24)=40` `2A+4B_(2)+6C_(3)rarrP+2Q` Limiting reagent `rarrA & B_(2)` so only 3 species will be left in final mixture. |
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