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Consider the following data for designing a taxiway for operating Boeing 707 – 320 airplane:Wheelbase = 17.70 mTread of main loading gear = 6.62 mTurning speed = 40 km/hCoefficient of friction between tyres and pavement surface = 0.13The turning radius of the taxiway will be1. 98.5 m2. 94.5 m3. 89.5 m4. 86.5 m |
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Answer» Correct Answer - Option 1 : 98.5 m Concept: The formula for comfort/centrifugal criteria is, \(e + f = \frac{{{V^2}}}{{125R}}\) Where, e = superelevation but for taxiway no superelevation is required, hence e = 0 f = coefficient of friction between tyres and pavement surface V = turning speed of an airplane R = turning radius of taxiway Calculation: Given, e = 0, f = 0.13, V = 40 km/hr \(e + f = \frac{{{V^2}}}{{125R}}\) \(0 + 0.13 = \frac{{{{40}^2}}}{{125 \times R}}\) \(R = \frac{{{{40}^2}}}{{125 \times 0.13}} = 98.46 \approx 98.5\;m\;\) |
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