Consider the following `E^o` values : `E^o _Fe^(3+)//FE^(2+)o = + 0.77 V` `E_(Sn^(2+)//Sn) =- 0.14 V` Under standard conditions the potential for reaction `Sn(s) +2Fe^(3+) (aq) rarr 2Fe^(2+) (sq) + Sn^(2+) (aq)` is.A. `0.91V`B. `1.40V`C. `1.68V`D. `0.63V`

Consider the following `E^o` values : `E^o _Fe^(3+)//FE^(2+)o = + 0.77

1.	Consider the following `E^o` values : `E^o _Fe^(3+)//FE^(2+)o = + 0.77 V` `E_(Sn^(2+)//Sn) =- 0.14 V` Under standard conditions the potential for reaction `Sn(s) +2Fe^(3+) (aq) rarr 2Fe^(2+) (sq) + Sn^(2+) (aq)` is.A. `0.91V`B. `1.40V`C. `1.68V`D. `0.63V`
Answer» Correct Answer - A `Sn -2e rarr Sn^(2+)` `(2Fe^(3+)+2e rarr 2Fe^(2+))/(Sn+2Fe^(3+) rarr Sn^(2+) +2Fe^(2+))` `E^(@)cell = (E_(C)^(@) -E_(A)^(@))_(R)` `=0.77V +0.14V = 0.91V`

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Consider the following `E^o` values : `E^o _Fe^(3+)//FE^(2+)o = + 0.77 V` `E_(Sn^(2+)//Sn) =- 0.14 V` Under standard conditions the potential for reaction `Sn(s) +2Fe^(3+) (aq) rarr 2Fe^(2+) (sq) + Sn^(2+) (aq)` is.A. `0.91V`B. `1.40V`C. `1.68V`D. `0.63V`

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