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Consider the following ` E^@` values . `E_(Fe^(3+)//Fe^(2+)^@ = + 0.77 V`, `E_(Sn^(2+)//Sn)^@=- 15. V` The `E_(cell)^@` for the reaction , `Sn (s) + 2Fe_(aq)^(3+) rarr 2 Fe_(aq.)^(2+) + Sn_(aq.)^(2+) is :A. `-0.58 V`B. `-0.30 V`C. `+0.30V`D. `+0.58 V` |
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Answer» Correct Answer - c At anode `: Fe(s) rarr Fe^(2+)(aq)+2e^(-)` `(` hald oxidation `)` At cathode `: Sn^(2+)(aq)+2e^(-) rarr Sn(s)` `(` half reduction `)` `ulbar(Cell reaction : Fe(s)+Sn^(2+)(aq)rarr Fe^(2+)(aq)+Sn(s))` `E^(c-)._(cell)=(E^(c-)._(red))_(c)-(E^(c-)._(red))_(a)` `=(-0.14)-(0.44)=0.30V.` |
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