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Consider the following equation in x and y: `(x-2y-1)^2 + (4x+3y-4)^2 + (x-2y-1)(4x+3y-4) =0` How many solutions to `(x, y)` with `x, y` real, does the equation haveA. zeroB. exactly oneC. exactly twoD. more than two |
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Answer» Correct Answer - B For solution `x-2y-1=0` and `4x+3y-4=0` |
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