Consider the following equilibrium in a closed container: N_(2)O_(4) (g) hArr2 NO_(2)(g) At a fixed temperature , the volume of the reaction container is halved . For this change , which of the following statement , holds true regarding the equilibrium constant (K_(p)) and degree of dissociation (alpha) ?

Consider the following equilibrium in a closed container: N_(2)O_(4) (

1.	Consider the following equilibrium in a closed container: N_(2)O_(4) (g) hArr2 NO_(2)(g) At a fixed temperature , the volume of the reaction container is halved . For this change , which of the following statement , holds true regarding the equilibrium constant (K_(p)) and degree of dissociation (alpha) ?
Answer» neither `K_(p) "nor" alpha` CHANGES both `K_(p) and alpha ` CHANGE `K_(p) " changes but " alpha ` does not change `K_(p) ` does not change but `alpha` changes Solution :`K_(p)` is CONSTANT at constant temperature . As volume is halved , pressure will be DOUBLED . Hence, equilibrium will shift in the backward direction , i.e, degree of dissociation decreases .