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Consider the following figure at 500 K.Assuming ideal gas behaviour, calculate the total pressure if the barriers are removed from the compartment.Assume that the volume of barriers is negligible. |
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Answer» Correct Answer - 2.85 atm Number of moles of A,B,C and D are given as : `n_A=(PV)/(RT)=(1xx1)/(RT),n_B=(1.5xx2)/(RT)=(3)/(RT)` `n_C=(2.5xx4)/(RT)=(10)/(RT),n_D=(2xx3)/(RT)=(6)/(RT)` `n=n_A+n_B+n_C+n_D=(1+3+10+6)/(RT)=20/(RT)` Total pressure is given as `P_("Total")=(nRT)/Vimplies P_("Total")=20/(RT)xx(RT)/7=2.85` |
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