Consider the following process of decay, ._(92)^(234)U rarr ._(90)^(230)Th + ._(2)^(4)He, t_(1//2) = 250000 yr ._(90)^(230)Th rarr ._(88)^(226)Ra + ._(2)(4)He, r_(1//2) = 80000 yr ._(88)^(226)Ra rarr ._(86)^(222)Rn + ._(2)^(4)He, t_(1//2) = 1600 yr After the above process has occurred for a long tiem, a state is reached where for every two thorium atoms formed form ._(92)^(234)U one decomposes to from ._(88)^(226)Ra and for every two ._(88)^(226)Raformed, one decomposes. The ratio of ._(90)^(230)Th to ._(88)^(226)Ra will be:

Consider the following process of decay, ._(92)^(234)U rarr ._(90)^(2

1.	Consider the following process of decay, ._(92)^(234)U rarr ._(90)^(230)Th + ._(2)^(4)He, t_(1//2) = 250000 yr ._(90)^(230)Th rarr ._(88)^(226)Ra + ._(2)(4)He, r_(1//2) = 80000 yr ._(88)^(226)Ra rarr ._(86)^(222)Rn + ._(2)^(4)He, t_(1//2) = 1600 yr After the above process has occurred for a long tiem, a state is reached where for every two thorium atoms formed form ._(92)^(234)U one decomposes to from ._(88)^(226)Ra and for every two ._(88)^(226)Raformed, one decomposes. The ratio of ._(90)^(230)Th to ._(88)^(226)Ra will be:
Answer» `(25000)/(80000)` `(80000)/(1600)` `(250000)/(1600)` `(250000xx1600)/(80000)` SOLUTION :Follow RADIOACTIVE equillibrium. `(N_(A))/(N_(B)) = (t_((1//2)A))/ (t_((1//2)B))`