1.

Consider the following reaction between zinc and oxygen and choose the corret options out of the options given below : 2Zn (s) + O_(2)(g)rarr 2ZnO(s), DeltaH= - 693.8 kJ mol^(-1)

Answer»

The enthalpy of two molesof ZnO is less than the TOTAL enthalpyof two moles of Zn and one mole of oxygen by 693.8kJ
The enthalpy of two enthalpy of two molesof ZnO is more than the totalenthalpy of two moles of Zn and one mole of oxygen by 693.8 Kj
693.8 kJ `mol^(-1)` energy is evolvedin the reaction
`693.8 kJ mol^(-1)` energy is absorbed in the reaction.

SOLUTION :`DeltaH = H_(p) -H_(R)`. A negative value of `DeltaH `SHOWS that `H_(r)GTH _(p) `or `H_(p)lt H_(R)`, i.e.,enthalpy of two molesof ZnOis less than the enthalpyof two moles of zinc and one moleof oxygen by 693.8kJ , As `H_(R)gt H_(P)`, 693.8 kJ mol^(-1)` of energyis evolvedin the reaction.


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