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Consider the following reaction:Here, A, B, C and D respectively are: A. A = Conc. HCl; B = Fe; C = NH4OH; D = PbO B. A = Conc. H2SO4; B = Fe; C = NH4OH; D = Pb(NO3)2 C. A = Conc. H2SO4; B = Fe; C = NH3; D= Pb(NO3)2 D. A = Conc. HCl; B = Fe; C = NH3; D =PbO |
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Answer» Step 1: When sodium chloride reacts with conc. H2SO4, it forms hydrogen chloride (HCl) and sodium sulphate (Na2SO4). The reaction that takes place is: 2NaCl + conc. H2SO4→ 2HCl + Na2SO4 Thus, A is concentrated H2SO4 Step 2: When hydrogen chloride reacts with iron metal (Fe), it forms iron (II) chloride (FeCl2) and hydrogen gas (H2). The reaction that takes place is: Fe + HCl → FeCl2 + H2 Thus, B is Fe. Step 3: When hydrogen chloride reacts with ammonia (NH3), it forms ammonium chloride (NH4Cl). The reaction that takes place is: NH3 + HCl → NH4Cl Thus, C is ammonia (NH3). Step 4: When hydrogen chloride reacts with lead nitrate [Pb(NO3)2], it forms lead chloride (PbCl2) and nitric acid (HNO3) . The reaction that takes place is: Pb(NO3)2 + HCl → PbCl2 + HNO3 Thus, D is lead nitrate [Pb(NO3)2] |
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