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consider the following reaction, `Na_(2)CO_(3) + 2HCl to 2NaCl + H_(2)O + CO_(2)` Equivalent weight of `Na_(2)CO_(3)` isA. `M/2`B. MC. 2MD. `M/4` |
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Answer» a) `Na_(2)CO_(3) + 2HCl to 2NaCl = H_(2)O + CO_(2)` In the above reaction, equivalent weight of `Na_(2)CO_(3)` is `M/2` because 2 moles of `Na^(+)` beign transferred per mole of `Na_(2)CO_(3)`. |
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