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Consider the following reactions: 2Na + 2NH_(3) rightarrow 2NaNH_(2) + H_(2)(g)……………..(i) 2NaNH_(2) + C rightarrow Na_(2)CN_(2) + 2H_(2)(g)…………….(ii) Na_(2)CN_(2) + C rightarrow 2NaCN……………….(iii) 51 gm dry ammonia gas is passed over excess heated sodium to form sodamide NaNH_(2) which is further reacted with carbon (excess) to finally form NaCN. Find the total volume of H_(2)(g) evolved at 0.5 atm, 273 K. |
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Answer» 201.6 L |
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