InterviewSolution
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InterviewSolution
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Consider the following reactions in which all the reactants and the products are in gaseous state None `2PQhArrP_(2)+Q_(2)," "K_(1)=2.5xx10^(5)` `PQ+1//2R_(2)hArrPQR," "K_(2)=5xx10^(-3)` The value of `K_(1)` for the equlibrium `1//2P_(2)+1//2Q_(2)+1//2R_(2)hArrPQR, is`A. `2.5xx10^(-3)`B. `2.5xx10^(3)`C. `1.0xx10^(-5)`D. `5xx10^(3)` |
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Answer» Correct Answer - C Given, `2PQhArrP_(2)+Q_(2)` `K_(1)=([P_(2)][Q_(2)])/([PQ]^(2))=2.5xx10^(5)` `PQ+1//2R_(2)hArrPQR.` `K_(2)=([PQR])/([PQ][R_(2)]^(1//2))=5xx10^(-3)` Required equlibrium is: `1//2P_(2)+1//2Q_(2)+1//2R_(2)hArrPQR,` `K_(3)=([PQR])/([P_(2)]^(1//2)[Q_(2)]^(1//2)[R_(2)]^(1//2))` `K_(3)=K_(2)xxsqrt((1)/(K_(1)))` `=5xx10^(-3)xxsqrt((1)/(2.5xx10^(5)))=(5xx10^(-3))/(0.5xx10^(3))=1xx10^(-5)` |
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