Consider the following relatoin for EMF of an electrochemical cell (i) EMF of cell =(Oxidation potential of anode) -(Reduction potenital of cathode ) (ii) EMF of cell =(oxidation potential of anode ) + (Reduction potential of cathode ) (iii) EMF of cel =(Reducation potential of anode ) +( Reduction potenital of cathode )(iv) EMF of cell =(oxidation potential of anode ) -(oxidation potentialof cathode) which of the abvoe realtions are correct

Consider the following relatoin for EMF of an electrochemical cell (i)

1.	Consider the following relatoin for EMF of an electrochemical cell (i) EMF of cell =(Oxidation potential of anode) -(Reduction potenital of cathode ) (ii) EMF of cell =(oxidation potential of anode ) + (Reduction potential of cathode ) (iii) EMF of cel =(Reducation potential of anode ) +( Reduction potenital of cathode )(iv) EMF of cell =(oxidation potential of anode ) -(oxidation potentialof cathode) which of the abvoe realtions are correct
Answer» (iii) and (i) (i) and (ii) (iii) and (IV) (ii) and (iv) Solution :We KNOW that oxidation POTENTIAL =- reduction potential and VICE versa `therefore`EMF of the cell =Reduction potential of cathode - Reduction potential of anode =Reduction potential of cathode + Oxidation potential of anode=Oxdiation potential of anode - oxidationpotential of cathode Thus option (d) is CORRECT