1.

Consider the following reversible reaction at equilibrium, A + B hArr C, If the concentration of the reactants A and B are doubled,then the equilibrium constant willl………………………. .

Answer»

be DOUBLED
BECOME one fourth
be halved
remain the same

Solution :`A + BhArr C `
`K_C = ([C])/([A][B])`
If [A] and [B] are doubled, [C] increases 4 times to MAINTAIN`K_C` as constant.
`:.` EQUILIBRIUM constant will remain the same.


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