1.

Consider the following set ofreactions: CHCl_(2)COOH+NaOH to CHCl_(2)COONa+H_(2)O "" DeltaH_(1)=-12830 Cal HCl+NaOH to NaCl to NaCl+H_(2)O "" DeltaH_(2)=-13680 Cal. NH_(4)OH+HCl to NH_(4)Cl+H_(2)O "" DeltaH_(3)=-12270 Cal. Select the correct option(s) :

Answer»

Enthalpy of neutralization of `CHCl_(2)COOH` by `NH_(4)OH` is `-11420 Cal.`
Enthalpy of DISSOCIATION of `NH_(4)OH=1410 Cal`
Enthalpy of dissociatiion of `NH_(4)OH=1410 Cal `.
Enthalpy change for the reaction `H_(2)O to H^(+)+OH^(-) is -13680 Cal `

Solution :(A),( C)
`DeltaH=DeltaH_(1)+DeltaH_(3)-DeltaH_(2)`
`=-(12830+12270-13680)`
`=-11420 Cal`
(B) `DeltaH_(2)-DeltaH_(1)=13680-12830`
`=850 Cal`
(C) `DeltaH_(2)-Delta_(3)=13680-12270`
`=1410 Cal`
(D) `H_(2)O to H^(+)+OH^(-)`
`=+13680K`


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