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Consider the following species : CN^(+), CN^(-), NO and CN Which one of these will have the highestbond order ? |
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Answer» `CN^(+)` ` sigma^(**) (2s)^(2), sigma (2p_(z))^(2) , pi(2p_(x))^(2)` `pi (2p_(y))^(2) . Pi^(**) (2p_(x))^(1) = pi^(**) (2p_(y))^(0)` B.O. ` = (10 - 5)/(2) = 2.5 ` `CN^(-) (14 e^(-)) : sigma(1s)^(2), sigma^(**) (1s)^(2), sigma (2s)^(2)` , ` sigma^(**) (2s)^(2) , pi (2p_(x))^(2) = pi (2p_(y))^(2)` `sigma (2p_(z))^(2)` B.O. ` = (10- 4)/(2) = 3 ` ` CN (13 e^(-)) : sigma(1s)^(2), sigma^(**) (1s)^(2), sigma (2s)^(2)` , ` sigma^(**) (2s)^(2) , pi (2p_(x))^(2) = pi (2p_(y))^(2)` `sigma (2p_(z))^(1)` B.O.`= (9-4)/(2) = 2.5 ` `CN (12 e^(-)) : sigma(1s)^(2), sigma^(**) (1s)^(2), sigma (2s)^(2)` , `sigma^(**) (2s)^(2) , pi (2p_(x))^(2) = pi (2p_(y))^(2)` B.O. ` = (8 - 4)/(2) = 2 ` Hence , `CN^(-)` has the highest bond order . |
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