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Consider the following species: `N^(3-)`,`O^(2-)`,`F^(ө)`,`Na^(o+)`,`Mg^(2+)` and `Al^(3+)` a. What is common in them? b. Arrange them in the order of increasing ionic radii. |
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Answer» a. Each one of these ion contains `10` elections and hence all are isoelectronic ions. b. The ionic radii of isoelectronic ions decrease with the increase in the magnitude of the nuclear charge. For example, consider the isoelectronic ions: `N^(3-),O^(2-),F^(ө),Na^(o+),Mg^(2+)` and `Al^(3+)` . All these ions have `10` electrons but their nuclear charges increase in the order: `N^(3-)(+7),O^(2-)(+8),F^(ө)(+9),Na^(o+)(+11),Mg^(2+)(+12)` and `Al^(3+)(+13)`. Therefore, their ionic radii decrease in the order : `N^(3-)gtO^(2-)gtF^(ө)gtNa^(o+)gtMg^(2+)gtAl^(3+)`. |
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