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Consider the following statements A and B. Identify the correct choice in the given answers A. In a one dimensional perfectly elastic collision between two moving bodies of equal masses the bodies merely exchange their velocities after collision. B. If a lighter body at rest suffers perfectly elastic collision with a very heavy body moving with a certain velocity, then after collision both travel with same velocity. |
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Answer» A and B are correct Using the LAWS of conservation of LINEAR momentum and energy, the velocities of two bodies after perfectly ELASTIC collision are given by `v_1=((m_1+m_2)u_1)/(m_1+m_2)+(2m_2u_2)/(m_1+m_2)`...(i) `v_2=(2m_1u_1)/(m_1+m_2)+((m_2+m_1)u_2)/(m_1+m_2)`...(ii) where `m_1` and `m_2` are the masses of two bodies and `u_1` and `u_2` are the velocities of two bodies before collision. If `m_1= m_2`,then From (i) and (ii), we get `v_1=u_2 and v_2=u_1` i.e., in perfectly elastic collision of two MOVING bodies ofequal masses, the bodies merely exchange their velocities after collision. Thus, statement A is correct. For B: In Eqs. (i) and (i), If `m_2lt ltm_1` and `u_2= 0`, then `v_1=u_1 and v_2 = 2u_1` Thus, statement B is wrong. |
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