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Consider the following statements A and B. Identify the correct choice in the given answers A. In a one dimensional perfectly elastic collision between two moving bodies of equal masses the bodies merely exchange their velocities after collision. B. If a lighter body at rest suffers perfectly elastic collision with a very heavy body moving with a certain velocity, then after collision both travel with same velocity.A. A and B are correctB. Both A and B are wrongC. A is correct, B is wrongD. A is wrong, B is correct |
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Answer» Correct Answer - C For A: Using the laws of conservation of linear momentum and energy, the velocities of two bodies after perfectly elastic collision are given by `v_1=((m_1+m_2)u_1)/(m_1+m_2)+(2m_2u_2)/(m_1+m_2)`...(i) `v_2=(2m_1u_1)/(m_1+m_2)+((m_2+m_1)u_2)/(m_1+m_2)`...(ii) where `m_1` and `m_2` are the masses of two bodies and `u_1` and `u_2` are the velocities of two bodies before collision. If `m_1= m_2`, then From (i) and (ii), we get `v_1=u_2 and v_2=u_1` i.e., in perfectly elastic collision of two moving bodies ofequal masses, the bodies merely exchange their velocities after collision. Thus, statement A is correct. For B: In Eqs. (i) and (i), If `m_2lt lt m_1` and `u_2= 0`, then `v_1=u_1 and v_2 = 2u_1` Thus, statement B is wrong. |
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