1.

Consider the following two reactions : (i) "Propene "+H_(2) rarr "Propane, "DeltaH_(1) (ii) "Cyclopropane"+H_(2)rarr"Propane, "DeltaH_(2) Then, DeltaH_(2)-DeltaH_(1) will be

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0
`2BE_(C-C)-BE_(C=C)`
`BE_(C=C)`
`2BE_(C=C)-BE_(C-C)`

Solution :`CH_(3)-CH=CH_(2)+H_(2) rarr CH_(2)+H_(2) rarr CH_(3)-CH_(2)-CH_(3)`,
`DeltaH_(1)=(BE_(C=C)+BE_(H-H))-(2BE_(C-H)+BE_(C-C))`


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