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Consider the follwing complexes ion `P,Q` and `R` `P =[FeF_(6)]^(3-), Q=[V(H_(2)O)_(6)]^(2+)` and `R=[Fe(H_(2)O)_(6)]^(2+)` The correct order of the complex ions, according to their spin only magnetic moment values (inBM) is .A. `R lt Q lt P`B. `Q lt P lt R`C. `Q lt R lt P`D. `R lt P lt Q` |
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Answer» Correct Answer - C `P = [FeF_(6)]^(3-) implies Fe^(3+) (3d^(5)) implies 5` unpaired `bar e` s `Q = [V(H_(2)O)_(6)]^(2+) implies V^(2+)(3d^(3)) implies 3` unpaired `bar e` s `R = [Fe(H_(2)O)_(6)]^(2+) implies Fe^(2+) (3d^(6)) 4` unpaired `bar e` s Since both `F^(-)` and `H_(2)O` are weak field ligands, the no. of unpaired electrons remains unchanged during the formation of complex ion. Thus option (3) is correct. |
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