Consider the four sets A,B,C and D defined as A={a:a=8(log4(x))3+4log√2(x4), x>0} B={b:b=20+13(logx2)2, x>0} C={c∈N:c∈A∩B for same x>0} D={x∈Z:(x−2)2(15x2−56x+17)<0} Then the number of elements in C×D is

Consider the four sets A,B,C and D defined as A={a:a=8(log4(x))3+4log�

1.	Consider the four sets A,B,C and D defined as A={a:a=8(log4(x))3+4log√2(x4), x>0} B={b:b=20+13(logx2)2, x>0} C={c∈N:c∈A∩B for same x>0} D={x∈Z:(x−2)2(15x2−56x+17)<0} Then the number of elements in C×D is
Answer» Consider the four sets $A, B, C$ and $D$ defined as $A = {a : a = 8 ({log}_{4} (x))^{3} + 4 {log}_{\sqrt{2}} (x^{4}), x > 0}$ $B = {b : b = 20 + \frac{13}{({log}_{x} 2)^{2}}, x > 0}$ $C = {c \in N : c \in A \cap B for same x > 0}$ $D = {x \in Z : (x - 2)^{2} (15 x^{2} - 56 x + 17) < 0}$ Then the number of elements in $C \times D$ is