1.

Consider the function f(x) = {{:( x^(2) - 1"," , -1 le x le 1) , ( lnx "," , 1 lt x le e):} Let f_(1) (x) = f (|x|) f_(2) (x) = |f(|x|)| f_(3) (x) = f (-x) Now answer the question Number of positive solution of the equation 2f_(2) (x) - 1= 0 is (are)

Answer»

`{{:( 4 + x , : , x GE 0 ),( 4 - x , : , x LT 0):}`
`{{:( 2 + x , : , x ge 0 ),( 2 - x , : , x lt 0):}`
`{{:( 4 + x , : , x lt 0 ),( 4 - x , : , x ge 0):}`
`{{:( 4 - x , : , x ge 0 ),(x , : , x lt 0):}`

ANSWER :C


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