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consider the function f(X) =x+cosx -a values of a for which f(X) =0 has exactly one negative root are |
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Answer» (0,1) Thus f(X) is increasing in `(-oo,oo)` as for f(x) =0 x is not forming an interval also f(X) =-cos x =0 or `x =(2n+1)(pi)/(2),nin Z` Hence there are infinite points of INFLECTION Now f(x) =1-a For POSITIVE root `1-alt0 or agt1` for negative root `1-agt 0 or a lt1` |
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