Consider the function f(x)=x2+bx+c, where D=b2−4c>0. If b<0, c>0 the – InterviewSolution

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1.	Consider the function f(x)=x2+bx+c, where D=b2−4c>0. If b<0, c>0 then the number of points of non-differentiability of g(x)=\|f(\|x\|)\| is
Answer» Consider the function $f (x) = x^{2} + b x + c,$ where $D = b^{2} - 4 c > 0.$ If $b < 0, c > 0$ then the number of points of non-differentiability of $g (x) = \| f (\| x \|) \|$ is

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