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Consider the ionisation of `H_(2) SO_(4)` as follow" `H_(2) SO_(4) + 2H_(2)P rarr 2H_(3) O^(o+) SO_(4)^(2-)` The total number of ions furnised by `100 mL` of `0.1 M` `H_(2)SO_(4)` will beA. `1.2 xx 10^(23)`B. `0.12 xx 10^(23)`C. `0.18 xx 10^(23)`D. `1.8 xx 10^(23)` |
Answer» Correct Answer - C 1 mol `H_(2) SO_(4) -= 2 "mol" H_(3)O^(O+) -= 1 "mol" SO_(4)^(2-)` `((100)/(1000) xx 0.1 = 0.01) -= 2 xx 0.01 + 0.01 = 0.03 "mo"` `= 0.18069 xx 10^(23)` |
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