InterviewSolution
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InterviewSolution
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Consider the isoelectronic species, `Na^(+),Mg^(2+),F^(-)` and `O^(2-)`. The correct order of increasing length of their radii is:A. `F^(-)O^(2-)ltMg^(2+)ltNa^(+)`B. `Mg^(2+)ltNa^(+)ltF^(-)ltO^(2-)`C. `O^(2-)ltF^(-)ltNa^(+)ltMg^(2+)`D. `O^(2-)ltF^(-)ltMg^(2+)ltNa^(+)` |
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Answer» Correct Answer - B For isoelectronic species,ionic radii decrease with increase in nuclear charge(I.e.,no. of protons).Thus,the cation with greater +Ve charge will have a smaller radius and the anion with greater -Ve charge will have a larger radius.Thus,the correct order of increasing ionic radii is `Mg^(2+)ltNa^(+)ltF^(-)ltO^(2-)` |
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