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Consider the molecules NH_(2) ^(-) , NH_(3) , NH_(4)^(+) . Arrange them in the decreasing order of bond angles and give reason for your arrangement. |
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Answer» Solution :(i) The decreasing ORDER of bond angles is : `NH_(4)^(+) gt NH_(3) gt NH_(2)^(-)` (ii) The N-atoms in all the THREE molecules are `sp^(3)` hybridised (iii) The number of lonw - pair of ELECTRONS present on nitrogen of `NH_(4)^(+), NH_(3)" and " 0, 1 ` and 2. (iv) Greater the number of lone pairs , greater is the REPULSION and lesser is the bond angle. |
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