InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Consider the numbers `4^n`, where n is a natural number. Cheek whether there is any value of n for which `4^n`ends with the digit zero. |
|
Answer» `4^n = (2*2)^n = 2^n*2^n` For a number to be end with `0`, it should be divided by `2 and 5`. But, as we can see `4^n` can be divided by only `2 or 2^n`. It can not be divided by `5`. So, `4^n` can not end with digit zero for any natural number. |
|