1.

In the given figure, ABCD is a cyclic quadrilateral; O is the centre of the circle.If `/_BOD=160^@`, then find `/_BPD`.

Answer» BD,`theta and theta/2`
`/_BAD=1/2/_BOD=1/2*160=80`
ABPD is also cyclic quadrilateral.
`/_BAD+/_BPD=180^0`
`/_BPD=180-80=100`
`/_BPD=100^0`.


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