InterviewSolution
Saved Bookmarks
| 1. |
In the given figure, ABCD is a cyclic quadrilateral; O is the centre of the circle.If `/_BOD=160^@`, then find `/_BPD`. |
|
Answer» BD,`theta and theta/2` `/_BAD=1/2/_BOD=1/2*160=80` ABPD is also cyclic quadrilateral. `/_BAD+/_BPD=180^0` `/_BPD=180-80=100` `/_BPD=100^0`. |
|